Whenever hydrogen atom emits a photon in the Balmer series –
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(b, c)
Any transition in the Balmer series must end up at n = 2. This must be followed by the transition from n = 2 to n = 1 emitting a photon of energy 10.2 eV. Which corresponds to a wavelength of about 122 nm. This belongs to the Lyman series.
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